物理
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Thermal Stress Calculator.
Calculate stress in a fully constrained uniaxial material.
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输入时结果会更新。
Results update automatically as you type.
Use Cases
Engineering design of constrained components
Determine the stress that will develop in a component that is rigidly fixed at both ends when it experiences a temperature change, helping to assess if the material can withstand it.
Example: A steel rail with E=200 GPa, α=12e-6 1/K, ΔT=50 K → stress = 120 MPa.
Material selection for temperature-varying environments
Compare different materials to see which produces lower thermal stress under the same constraints and temperature change, aiding in material choice.
Example: Compare aluminum vs. steel for a fixed beam with a 30 K temperature rise.
Frequently Asked Questions
- What is thermal stress?
- Thermal stress is the internal stress that develops in a material when it is fully constrained and subjected to a temperature change. It is calculated as the product of Young's modulus, the expansion coefficient, and the temperature change.
- How is thermal stress calculated?
- The calculator uses the formula: Thermal Stress = Young's Modulus × Expansion Coefficient × Temperature Change. This assumes the material is fully constrained and cannot expand or contract freely.
- What units should I use?
- Enter Young's modulus in pascals (Pa), expansion coefficient in per kelvin (1/K), and temperature change in kelvin (K). The result will be in pascals (Pa).
Tips & Common Mistakes
Tips
- Ensure the material is truly fully constrained; if it can expand partially, the stress will be lower.
- Use consistent units: convert all inputs to SI units (Pa, 1/K, K) before calculating.
- Remember that thermal stress is independent of the material's length or cross-sectional area.
- For temperature changes, use the difference between final and initial temperatures in kelvin.
Common Mistakes to Avoid
- Forgetting to convert temperature change from Celsius to Kelvin; the difference is the same, but ensure you use the correct value.
- Using the expansion coefficient in per °C instead of per K; they are numerically equal for differences, but be consistent.
- Assuming the material is not fully constrained when it is, leading to an underestimation of stress.
Last updated: August 13, 2026