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Physique

Calculatrice vérifiée avec une formule transparente

Physique

Centrifugal Pump Power Calculator.

Calculates the hydraulic power required to pump a fluid based on flow rate, head, and fluid density.

Les résultats se mettent à jour en direct pendant que vous tapez.
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Vos entrées

Comment ça marche

  1. 1

    Convert flow rate from m³/h to m³/s by dividing by 3600.

  2. 2

    Multiply by gravitational acceleration (9.81 m/s²).

  3. 3

    Multiply by head and fluid density.

  4. 4

    Divide by 1000 to get power in kilowatts.

(flow_rate / 3600) * 9.81 * head * density / 1000

Questions fréquentes

What is hydraulic power?

It is the theoretical power needed to move fluid at a given flow rate and head, ignoring pump and motor inefficiencies.

How do I account for pump efficiency?

Divide the hydraulic power by the pump efficiency (as a decimal) to get the shaft power required.

Why is density important?

Denser fluids require more energy to lift, so power increases with density.

Explorer cette catégorie de calculatrices

Résultats

Formule vérifiée

Hydraulic power

2,725kW

Estimation à titre indicatif uniquement — vérifiez les décisions importantes avec un professionnel approprié.

Comment ça marche

Calculates the hydraulic power required to pump a fluid based on flow rate, head, and fluid density.

  1. Convert flow rate from m³/h to m³/s by dividing by 3600.
  2. Multiply by gravitational acceleration (9.81 m/s²).
  3. Multiply by head and fluid density.
  4. Divide by 1000 to get power in kilowatts.

Formules

Les mathématiques derrière cette calculatrice, écrites pour que vous puissiez vérifier le résultat.

Hydraulic Power

P = (Q × ρ × g × H) / 1000

Power in kW equals flow rate (m³/s) times density (kg/m³) times gravity (9.81 m/s²) times head (m), divided by 1000.

Example:

Input: Q = 50 m³/h, H = 20 m, ρ = 1000 kg/m³

Calculation: (50/3600) × 1000 × 9.81 × 20 / 1000

Result: ≈ 2.73 kW

Cas d'utilisation réels

Où ce calcul apparaît dans la vie quotidienne.

Sizing a pump motor

Estimate the minimum motor power needed for a given duty.

Example: Selecting a motor for a 50 m³/h, 20 m head water pump.

Comparing pump options

Evaluate energy requirements for different flow and head conditions.

Example: Choosing between two pumps with different efficiencies.

Energy cost estimation

Calculate power consumption to estimate operating costs.

Example: Estimating annual electricity cost for a pumping system.

Conseils et erreurs courantes

Tips

  • Use actual fluid density for accurate results (e.g., 998 kg/m³ for water at 20°C).
  • Remember that hydraulic power is theoretical; actual power draw is higher due to losses.
  • Check units: flow rate must be in m³/h, head in meters, density in kg/m³.
  • For pump selection, divide by efficiency (e.g., 0.7 for 70%) to get shaft power.

Common Mistakes to Avoid

  • Forgetting to convert flow rate from m³/h to m³/s.
  • Using density of water for other fluids without checking.
  • Ignoring pump efficiency when sizing the motor.

Hypothèses et limites

  • Use the stated inputs and units.
  • Results are estimates for planning and education.
  • Check measurements and source data before making an important decision.