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Physik

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Physik

Centrifugal Pump Power Calculator.

Calculates the hydraulic power required to pump a fluid based on flow rate, head, and fluid density.

Ergebnisse werden während der Eingabe live aktualisiert.
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Ihre Eingaben

So funktioniert es

  1. 1

    Convert flow rate from m³/h to m³/s by dividing by 3600.

  2. 2

    Multiply by gravitational acceleration (9.81 m/s²).

  3. 3

    Multiply by head and fluid density.

  4. 4

    Divide by 1000 to get power in kilowatts.

(flow_rate / 3600) * 9.81 * head * density / 1000

Häufig gestellte Fragen

What is hydraulic power?

It is the theoretical power needed to move fluid at a given flow rate and head, ignoring pump and motor inefficiencies.

How do I account for pump efficiency?

Divide the hydraulic power by the pump efficiency (as a decimal) to get the shaft power required.

Why is density important?

Denser fluids require more energy to lift, so power increases with density.

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Ergebnisse

Formel geprüft

Hydraulic power

2,725kW

Fragen Sie alles

Schätzung nur zur allgemeinen Orientierung – wichtige Entscheidungen mit einem geeigneten Fachmann verifizieren.

So funktioniert es

Calculates the hydraulic power required to pump a fluid based on flow rate, head, and fluid density.

  1. Convert flow rate from m³/h to m³/s by dividing by 3600.
  2. Multiply by gravitational acceleration (9.81 m/s²).
  3. Multiply by head and fluid density.
  4. Divide by 1000 to get power in kilowatts.

Formeln

Die Mathematik hinter diesem Rechner, aufgeschrieben, damit Sie das Ergebnis überprüfen können.

Hydraulic Power

P = (Q × ρ × g × H) / 1000

Power in kW equals flow rate (m³/s) times density (kg/m³) times gravity (9.81 m/s²) times head (m), divided by 1000.

Example:

Input: Q = 50 m³/h, H = 20 m, ρ = 1000 kg/m³

Calculation: (50/3600) × 1000 × 9.81 × 20 / 1000

Result: ≈ 2.73 kW

Anwendungsfälle im Alltag

Wo diese Berechnung im täglichen Leben vorkommt.

Sizing a pump motor

Estimate the minimum motor power needed for a given duty.

Example: Selecting a motor for a 50 m³/h, 20 m head water pump.

Comparing pump options

Evaluate energy requirements for different flow and head conditions.

Example: Choosing between two pumps with different efficiencies.

Energy cost estimation

Calculate power consumption to estimate operating costs.

Example: Estimating annual electricity cost for a pumping system.

Tipps und häufige Fehler

Tips

  • Use actual fluid density for accurate results (e.g., 998 kg/m³ for water at 20°C).
  • Remember that hydraulic power is theoretical; actual power draw is higher due to losses.
  • Check units: flow rate must be in m³/h, head in meters, density in kg/m³.
  • For pump selection, divide by efficiency (e.g., 0.7 for 70%) to get shaft power.

Common Mistakes to Avoid

  • Forgetting to convert flow rate from m³/h to m³/s.
  • Using density of water for other fluids without checking.
  • Ignoring pump efficiency when sizing the motor.

Annahmen und Einschränkungen

  • Use the stated inputs and units.
  • Results are estimates for planning and education.
  • Check measurements and source data before making an important decision.